[HackerRank - Java] Day 4 - 1. Grid Challenge

2023. 1. 29. 19:56Java/coding test

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Grid Challenge

Given a square grid of characters in the range ascii[a-z], rearrange elements of each row alphabetically, ascending. Determine if the columns are also in ascending alphabetical order, top to bottom. Return YES if they are or NO if they are not.

Example

gird=[abc,ade,efg]gird = ['abc', 'ade', 'efg']

The grid is illustrated below.

a b c
a d e
e f g

The rows are already in alphabetical order. The columns a a e, b d f and c e g are also in alphabetical order, so the answer would be YES. Only elements within the same row can be rearranged. They cannot be moved to a different row.

Function Description

Complete the gridChallenge function in the editor below.

gridChallenge has the following parameter(s):

  • string grid[n]: an array of strings

Returns

  • string: either YES or NO

Input Format

The first line contains tt, the number of testcases.

Each of the next tt sets of lines are described as follows:

  • The first line contains nn, the number of rows and columns in the grid.
  • The next nn lines contains a string of length nn

Constraints

1<=t<=1001 <= t <= 100
1<=n<=1001 <= n <= 100

Each string consists of lowercase letters in the range ascii[a-z]

Output Format

For each test case, on a separate line print YES if it is possible to rearrange the grid alphabetically ascending in both its rows and columns, or NO otherwise.

Sample Input

STDIN   Function
-----   --------
1       t = 1
5       n = 5
ebacd   grid = ['ebacd', 'fghij', 'olmkn', 'trpqs', 'xywuv']
fghij
olmkn
trpqs
xywuv

Sample Output

YES

Explanation

The 5x5 grid in the 1 test case can be reordered to

abcde
fghij
klmno
pqrst
uvwxy

This fulfills the condition since the rows 1, 2, ..., 5 and the columns 1, 2, ..., 5 are all alphabetically sorted.


static String gridChallenge(List<String> grid) {
    String prevStr = sort(grid.get(0));
    for (int i = 1; i < grid.size(); i++) {
        String sortedStr = sort(grid.get(i));
        for (int j = 0; j < sortedStr.length(); j++) {
            if(prevStr.charAt(j) > sortedStr.charAt(j)) {
                return "NO";
            }
        }
    }
    return "YES";
}

static String sort(String s) {
    char[] arr = s.toCharArray();
    Arrays.sort(arr);
    return new String(arr);
}
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